TheoryFree OAT Optometry Admission Prep Practice Test
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OAT Optometry Admission Prep Questions
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Q1Which reaction mechanism best describes the conversion of 2-bromopropane to propene when heated with potassium hydroxide in ethanol?
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✓ Correct answer: E2 elimination
This reaction involves the removal of HBr from 2-bromopropane to form propene. This is an E2 elimination reaction, which occurs in a single step where the base (OH-) abstracts a proton while the bromine leaves, forming a double bond.
Q2Which spectroscopic technique would be most useful for distinguishing between 1-hexanol and hexanal?
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✓ Correct answer: IR spectroscopy
IR spectroscopy can easily distinguish between these compounds because 1-hexanol shows a broad O-H stretching band at approximately 3200-3600 cm^-1, while hexanal shows a characteristic C=O stretching band around 1700-1740 cm^-1.
Q3Which statement about the structure of (R)-2-butanol is correct?
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✓ Correct answer: The hydroxyl group is on the second carbon, and the priorities decrease clockwise when the hydrogen is away from the viewer
In (R)-2-butanol, the OH group is attached to the second carbon, making it a secondary alcohol. According to the R/S system, the R configuration means that when the lowest priority group (H) is placed away from the viewer, the priorities of the remaining groups decrease in a clockwise direction.
Q4What is the IUPAC name for the compound CH3CH2CH(CH3)CH2CH2COOH?
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✓ Correct answer: 3-methylhexanoic acid
The longest carbon chain containing the carboxylic acid group has 6 carbons, making it hexanoic acid. There is a methyl group attached to the third carbon, so the name is 3-methylhexanoic acid.
Q5Which reagent would be most appropriate for converting cyclohexanone to cyclohexanol?
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✓ Correct answer: NaBH4
NaBH4 (sodium borohydride) is a mild reducing agent that selectively reduces ketones to alcohols without affecting other functional groups like carboxylic acids or esters. This makes it ideal for converting cyclohexanone to cyclohexanol.
Q6Which of the following compounds would have the highest boiling point?
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✓ Correct answer: 1-pentanol
1-pentanol has the highest boiling point among these compounds because alcohols can form hydrogen bonds. Pentane and 1-pentene only have weak van der Waals forces, while diethyl ether can form dipole-dipole interactions but not hydrogen bonds.
Q7In the 1H NMR spectrum of ethyl acetate (CH3COOCH2CH3), how many different sets of signals would you expect to observe?
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✓ Correct answer: 3
Ethyl acetate has three different types of protons: the methyl group attached to the carbonyl (CH3CO-), the methylene group of the ethyl part (-OCH2CH3), and the methyl group of the ethyl part (-OCH2CH3). Each of these will give a distinct signal in the 1H NMR spectrum.
Q8Which of the following compounds is chiral?
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✓ Correct answer: 2-butanol
2-butanol has a carbon atom (the second carbon) bonded to four different groups: -H, -OH, -CH3, and -CH2CH3. This makes it a chiral molecule with a stereocenter.
Q9What type of reaction occurs when alkenes react with hydrogen in the presence of a platinum catalyst?
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✓ Correct answer: Hydrogenation
When alkenes react with hydrogen ($$H_{2}$$) in the presence of a platinum catalyst, hydrogenation occurs. This is an addition reaction where the hydrogen atoms add across the double bond, converting the alkene to an alkane.
Q10Which statement about benzene is CORRECT?
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✓ Correct answer: It is aromatic because it has a planar ring with 6 π electrons
Benzene is aromatic because it has a planar ring with 4n+2 π electrons (where n=1, giving 6 π electrons). This arrangement leads to enhanced stability through electron delocalization, which is characteristic of aromatic compounds.
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