A paper bag contains 3 blue marbles, 2 red marbles, 4 green marbles and 1 white marble. Without replacement what is the probability of drawing a red marble on first attempt and green marble on the second attempt?

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TheoryPractice · Accepted Answer

4/45. On the first draw there are 10 marbles therefore the probability is getting a red is 2/10 or 1/5. On the second draw there are 9 marbles the probability of getting a green is 4/9. The events are independent thus multiply the two probabilities to determine first ball is red and second is green. 1/5 * 4/9 = 4/45.

A paper bag contains 3 blue marbles, 2 red marbles, 4 green marbles and 1 white marble. Without replacement what is the probability of drawing a red marble on first attempt and green marble on the second attempt?

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